- #1

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find [tex]\frac{dy^2}{dx^2}[/tex] in terms of t for...

x = 2cost - cos2t, y = 2sint + sin2t...

i got my answer to be [tex]\frac{1 + cost}{2sin^3t(1 -2cost)}[/tex]

the answer is given as [tex]\frac{-1}{sin^3t(2cost -1)}[/tex]

have i gone wrong somewhere...do i need to simplify further...the answer i got and the one that is given do have some similarities so i'm just wondering...???...